3.1.28 \(\int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx\) [28]

3.1.28.1 Optimal result
3.1.28.2 Mathematica [A] (verified)
3.1.28.3 Rubi [A] (verified)
3.1.28.4 Maple [C] (verified)
3.1.28.5 Fricas [A] (verification not implemented)
3.1.28.6 Sympy [F]
3.1.28.7 Maxima [F]
3.1.28.8 Giac [B] (verification not implemented)
3.1.28.9 Mupad [F(-1)]

3.1.28.1 Optimal result

Integrand size = 17, antiderivative size = 149 \[ \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx=-\frac {\cos (c+d x)}{b^2 d}+\frac {a^2 d \cos \left (c-\frac {a d}{b}\right ) \operatorname {CosIntegral}\left (\frac {a d}{b}+d x\right )}{b^4}-\frac {2 a \operatorname {CosIntegral}\left (\frac {a d}{b}+d x\right ) \sin \left (c-\frac {a d}{b}\right )}{b^3}-\frac {a^2 \sin (c+d x)}{b^3 (a+b x)}-\frac {2 a \cos \left (c-\frac {a d}{b}\right ) \text {Si}\left (\frac {a d}{b}+d x\right )}{b^3}-\frac {a^2 d \sin \left (c-\frac {a d}{b}\right ) \text {Si}\left (\frac {a d}{b}+d x\right )}{b^4} \]

output
a^2*d*Ci(a*d/b+d*x)*cos(-c+a*d/b)/b^4-cos(d*x+c)/b^2/d-2*a*cos(-c+a*d/b)*S 
i(a*d/b+d*x)/b^3+2*a*Ci(a*d/b+d*x)*sin(-c+a*d/b)/b^3+a^2*d*Si(a*d/b+d*x)*s 
in(-c+a*d/b)/b^4-a^2*sin(d*x+c)/b^3/(b*x+a)
 
3.1.28.2 Mathematica [A] (verified)

Time = 0.53 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.79 \[ \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx=\frac {a \operatorname {CosIntegral}\left (d \left (\frac {a}{b}+x\right )\right ) \left (a d \cos \left (c-\frac {a d}{b}\right )-2 b \sin \left (c-\frac {a d}{b}\right )\right )+b \left (-\frac {b \cos (c+d x)}{d}-\frac {a^2 \sin (c+d x)}{a+b x}\right )-a \left (2 b \cos \left (c-\frac {a d}{b}\right )+a d \sin \left (c-\frac {a d}{b}\right )\right ) \text {Si}\left (d \left (\frac {a}{b}+x\right )\right )}{b^4} \]

input
Integrate[(x^2*Sin[c + d*x])/(a + b*x)^2,x]
 
output
(a*CosIntegral[d*(a/b + x)]*(a*d*Cos[c - (a*d)/b] - 2*b*Sin[c - (a*d)/b]) 
+ b*(-((b*Cos[c + d*x])/d) - (a^2*Sin[c + d*x])/(a + b*x)) - a*(2*b*Cos[c 
- (a*d)/b] + a*d*Sin[c - (a*d)/b])*SinIntegral[d*(a/b + x)])/b^4
 
3.1.28.3 Rubi [A] (verified)

Time = 0.57 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {7293, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx\)

\(\Big \downarrow \) 7293

\(\displaystyle \int \left (\frac {a^2 \sin (c+d x)}{b^2 (a+b x)^2}-\frac {2 a \sin (c+d x)}{b^2 (a+b x)}+\frac {\sin (c+d x)}{b^2}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {a^2 d \cos \left (c-\frac {a d}{b}\right ) \operatorname {CosIntegral}\left (x d+\frac {a d}{b}\right )}{b^4}-\frac {a^2 d \sin \left (c-\frac {a d}{b}\right ) \text {Si}\left (x d+\frac {a d}{b}\right )}{b^4}-\frac {a^2 \sin (c+d x)}{b^3 (a+b x)}-\frac {2 a \sin \left (c-\frac {a d}{b}\right ) \operatorname {CosIntegral}\left (x d+\frac {a d}{b}\right )}{b^3}-\frac {2 a \cos \left (c-\frac {a d}{b}\right ) \text {Si}\left (x d+\frac {a d}{b}\right )}{b^3}-\frac {\cos (c+d x)}{b^2 d}\)

input
Int[(x^2*Sin[c + d*x])/(a + b*x)^2,x]
 
output
-(Cos[c + d*x]/(b^2*d)) + (a^2*d*Cos[c - (a*d)/b]*CosIntegral[(a*d)/b + d* 
x])/b^4 - (2*a*CosIntegral[(a*d)/b + d*x]*Sin[c - (a*d)/b])/b^3 - (a^2*Sin 
[c + d*x])/(b^3*(a + b*x)) - (2*a*Cos[c - (a*d)/b]*SinIntegral[(a*d)/b + d 
*x])/b^3 - (a^2*d*Sin[c - (a*d)/b]*SinIntegral[(a*d)/b + d*x])/b^4
 

3.1.28.3.1 Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 7293
Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v] 
]
 
3.1.28.4 Maple [C] (verified)

Result contains complex when optimal does not.

Time = 0.31 (sec) , antiderivative size = 402, normalized size of antiderivative = 2.70

method result size
risch \(-\frac {i \left (2 i b^{3} d^{2} x^{2}+4 i a \,b^{2} d^{2} x +2 i a^{2} b \,d^{2}\right ) \cos \left (d x +c \right )}{2 b^{3} d^{2} \left (b x +a \right ) \left (-d x b -d a \right )}+\frac {\left (2 a^{2} b \,d^{3} x +2 d^{3} a^{3}\right ) \sin \left (d x +c \right )}{2 b^{3} d^{2} \left (b x +a \right ) \left (-d x b -d a \right )}-\frac {i \cos \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (-\frac {i d \left (b x +a \right )}{b}\right ) a}{b^{3}}+\frac {i \cos \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (\frac {i d \left (b x +a \right )}{b}\right ) a}{b^{3}}-\frac {d \cos \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (-\frac {i d \left (b x +a \right )}{b}\right ) a^{2}}{2 b^{4}}-\frac {d \cos \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (\frac {i d \left (b x +a \right )}{b}\right ) a^{2}}{2 b^{4}}-\frac {\sin \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (-\frac {i d \left (b x +a \right )}{b}\right ) a}{b^{3}}-\frac {\sin \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (\frac {i d \left (b x +a \right )}{b}\right ) a}{b^{3}}+\frac {i d \sin \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (-\frac {i d \left (b x +a \right )}{b}\right ) a^{2}}{2 b^{4}}-\frac {i d \sin \left (\frac {d a -c b}{b}\right ) \operatorname {Ei}_{1}\left (\frac {i d \left (b x +a \right )}{b}\right ) a^{2}}{2 b^{4}}\) \(402\)
derivativedivides \(\frac {c^{2} d^{2} \left (-\frac {\sin \left (d x +c \right )}{\left (d a -c b +b \left (d x +c \right )\right ) b}+\frac {\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}+\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}}{b}\right )-\frac {2 c \,d^{2} \left (\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}-\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}\right )}{b}+\frac {2 d^{2} \left (d a -c b \right ) c \left (-\frac {\sin \left (d x +c \right )}{\left (d a -c b +b \left (d x +c \right )\right ) b}+\frac {\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}+\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}}{b}\right )}{b}-\frac {2 \left (d a -c b \right ) d^{2} \left (\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}-\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}\right )}{b^{2}}+\frac {\left (d^{2} a^{2}-2 a b c d +b^{2} c^{2}\right ) d^{2} \left (-\frac {\sin \left (d x +c \right )}{\left (d a -c b +b \left (d x +c \right )\right ) b}+\frac {\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}+\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}}{b}\right )}{b^{2}}-\frac {d^{2} \cos \left (d x +c \right )}{b^{2}}}{d^{3}}\) \(553\)
default \(\frac {c^{2} d^{2} \left (-\frac {\sin \left (d x +c \right )}{\left (d a -c b +b \left (d x +c \right )\right ) b}+\frac {\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}+\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}}{b}\right )-\frac {2 c \,d^{2} \left (\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}-\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}\right )}{b}+\frac {2 d^{2} \left (d a -c b \right ) c \left (-\frac {\sin \left (d x +c \right )}{\left (d a -c b +b \left (d x +c \right )\right ) b}+\frac {\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}+\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}}{b}\right )}{b}-\frac {2 \left (d a -c b \right ) d^{2} \left (\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}-\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}\right )}{b^{2}}+\frac {\left (d^{2} a^{2}-2 a b c d +b^{2} c^{2}\right ) d^{2} \left (-\frac {\sin \left (d x +c \right )}{\left (d a -c b +b \left (d x +c \right )\right ) b}+\frac {\frac {\operatorname {Si}\left (d x +c +\frac {d a -c b}{b}\right ) \sin \left (\frac {d a -c b}{b}\right )}{b}+\frac {\operatorname {Ci}\left (d x +c +\frac {d a -c b}{b}\right ) \cos \left (\frac {d a -c b}{b}\right )}{b}}{b}\right )}{b^{2}}-\frac {d^{2} \cos \left (d x +c \right )}{b^{2}}}{d^{3}}\) \(553\)

input
int(x^2*sin(d*x+c)/(b*x+a)^2,x,method=_RETURNVERBOSE)
 
output
-1/2*I/b^3/d^2*(2*I*a^2*b*d^2+4*I*a*b^2*d^2*x+2*I*b^3*d^2*x^2)/(b*x+a)/(-b 
*d*x-a*d)*cos(d*x+c)+1/2/b^3/d^2*(2*a^2*b*d^3*x+2*a^3*d^3)/(b*x+a)/(-b*d*x 
-a*d)*sin(d*x+c)-I/b^3*cos((a*d-b*c)/b)*Ei(1,-I*d*(b*x+a)/b)*a+I/b^3*cos(( 
a*d-b*c)/b)*Ei(1,I*d*(b*x+a)/b)*a-1/2*d/b^4*cos((a*d-b*c)/b)*Ei(1,-I*d*(b* 
x+a)/b)*a^2-1/2*d/b^4*cos((a*d-b*c)/b)*Ei(1,I*d*(b*x+a)/b)*a^2-1/b^3*sin(( 
a*d-b*c)/b)*Ei(1,-I*d*(b*x+a)/b)*a-1/b^3*sin((a*d-b*c)/b)*Ei(1,I*d*(b*x+a) 
/b)*a+1/2*I*d/b^4*sin((a*d-b*c)/b)*Ei(1,-I*d*(b*x+a)/b)*a^2-1/2*I*d/b^4*si 
n((a*d-b*c)/b)*Ei(1,I*d*(b*x+a)/b)*a^2
 
3.1.28.5 Fricas [A] (verification not implemented)

Time = 0.29 (sec) , antiderivative size = 202, normalized size of antiderivative = 1.36 \[ \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx=-\frac {a^{2} b d \sin \left (d x + c\right ) + {\left (b^{3} x + a b^{2}\right )} \cos \left (d x + c\right ) - {\left ({\left (a^{2} b d^{2} x + a^{3} d^{2}\right )} \operatorname {Ci}\left (\frac {b d x + a d}{b}\right ) - 2 \, {\left (a b^{2} d x + a^{2} b d\right )} \operatorname {Si}\left (\frac {b d x + a d}{b}\right )\right )} \cos \left (-\frac {b c - a d}{b}\right ) - {\left (2 \, {\left (a b^{2} d x + a^{2} b d\right )} \operatorname {Ci}\left (\frac {b d x + a d}{b}\right ) + {\left (a^{2} b d^{2} x + a^{3} d^{2}\right )} \operatorname {Si}\left (\frac {b d x + a d}{b}\right )\right )} \sin \left (-\frac {b c - a d}{b}\right )}{b^{5} d x + a b^{4} d} \]

input
integrate(x^2*sin(d*x+c)/(b*x+a)^2,x, algorithm="fricas")
 
output
-(a^2*b*d*sin(d*x + c) + (b^3*x + a*b^2)*cos(d*x + c) - ((a^2*b*d^2*x + a^ 
3*d^2)*cos_integral((b*d*x + a*d)/b) - 2*(a*b^2*d*x + a^2*b*d)*sin_integra 
l((b*d*x + a*d)/b))*cos(-(b*c - a*d)/b) - (2*(a*b^2*d*x + a^2*b*d)*cos_int 
egral((b*d*x + a*d)/b) + (a^2*b*d^2*x + a^3*d^2)*sin_integral((b*d*x + a*d 
)/b))*sin(-(b*c - a*d)/b))/(b^5*d*x + a*b^4*d)
 
3.1.28.6 Sympy [F]

\[ \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx=\int \frac {x^{2} \sin {\left (c + d x \right )}}{\left (a + b x\right )^{2}}\, dx \]

input
integrate(x**2*sin(d*x+c)/(b*x+a)**2,x)
 
output
Integral(x**2*sin(c + d*x)/(a + b*x)**2, x)
 
3.1.28.7 Maxima [F]

\[ \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx=\int { \frac {x^{2} \sin \left (d x + c\right )}{{\left (b x + a\right )}^{2}} \,d x } \]

input
integrate(x^2*sin(d*x+c)/(b*x+a)^2,x, algorithm="maxima")
 
output
-1/2*((cos(c)^2 + sin(c)^2)*x^2*cos(d*x + c) + (x^2*cos(d*x + c)^2*cos(c) 
+ x^2*cos(c)*sin(d*x + c)^2)*cos(d*x + 2*c) - 2*(((a*b^2*cos(c)^2 + a*b^2* 
sin(c)^2)*d*x^2 + 2*(a^2*b*cos(c)^2 + a^2*b*sin(c)^2)*d*x + (a^3*cos(c)^2 
+ a^3*sin(c)^2)*d)*cos(d*x + c)^2 + ((a*b^2*cos(c)^2 + a*b^2*sin(c)^2)*d*x 
^2 + 2*(a^2*b*cos(c)^2 + a^2*b*sin(c)^2)*d*x + (a^3*cos(c)^2 + a^3*sin(c)^ 
2)*d)*sin(d*x + c)^2)*integrate(x*cos(d*x + c)/(b^3*d*x^3 + 3*a*b^2*d*x^2 
+ 3*a^2*b*d*x + a^3*d), x) - 2*(((a*b^2*cos(c)^2 + a*b^2*sin(c)^2)*d*x^2 + 
 2*(a^2*b*cos(c)^2 + a^2*b*sin(c)^2)*d*x + (a^3*cos(c)^2 + a^3*sin(c)^2)*d 
)*cos(d*x + c)^2 + ((a*b^2*cos(c)^2 + a*b^2*sin(c)^2)*d*x^2 + 2*(a^2*b*cos 
(c)^2 + a^2*b*sin(c)^2)*d*x + (a^3*cos(c)^2 + a^3*sin(c)^2)*d)*sin(d*x + c 
)^2)*integrate(x*cos(d*x + c)/((b^3*d*x^3 + 3*a*b^2*d*x^2 + 3*a^2*b*d*x + 
a^3*d)*cos(d*x + c)^2 + (b^3*d*x^3 + 3*a*b^2*d*x^2 + 3*a^2*b*d*x + a^3*d)* 
sin(d*x + c)^2), x) + (x^2*cos(d*x + c)^2*sin(c) + x^2*sin(d*x + c)^2*sin( 
c))*sin(d*x + 2*c))/(((b^2*cos(c)^2 + b^2*sin(c)^2)*d*x^2 + 2*(a*b*cos(c)^ 
2 + a*b*sin(c)^2)*d*x + (a^2*cos(c)^2 + a^2*sin(c)^2)*d)*cos(d*x + c)^2 + 
((b^2*cos(c)^2 + b^2*sin(c)^2)*d*x^2 + 2*(a*b*cos(c)^2 + a*b*sin(c)^2)*d*x 
 + (a^2*cos(c)^2 + a^2*sin(c)^2)*d)*sin(d*x + c)^2)
 
3.1.28.8 Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 1120 vs. \(2 (152) = 304\).

Time = 0.33 (sec) , antiderivative size = 1120, normalized size of antiderivative = 7.52 \[ \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx=\text {Too large to display} \]

input
integrate(x^2*sin(d*x+c)/(b*x+a)^2,x, algorithm="giac")
 
output
((b*x + a)*a^2*(b*c/(b*x + a) - a*d/(b*x + a) + d)*d^2*cos(-(b*c - a*d)/b) 
*cos_integral(((b*x + a)*(b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/ 
b) - a^2*b*c*d^2*cos(-(b*c - a*d)/b)*cos_integral(((b*x + a)*(b*c/(b*x + a 
) - a*d/(b*x + a) + d) - b*c + a*d)/b) + a^3*d^3*cos(-(b*c - a*d)/b)*cos_i 
ntegral(((b*x + a)*(b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/b) + ( 
b*x + a)*a^2*(b*c/(b*x + a) - a*d/(b*x + a) + d)*d^2*sin(-(b*c - a*d)/b)*s 
in_integral(((b*x + a)*(b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/b) 
 - a^2*b*c*d^2*sin(-(b*c - a*d)/b)*sin_integral(((b*x + a)*(b*c/(b*x + a) 
- a*d/(b*x + a) + d) - b*c + a*d)/b) + a^3*d^3*sin(-(b*c - a*d)/b)*sin_int 
egral(((b*x + a)*(b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/b) + 2*( 
b*x + a)*a*b*(b*c/(b*x + a) - a*d/(b*x + a) + d)*d*cos_integral(((b*x + a) 
*(b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/b)*sin(-(b*c - a*d)/b) - 
 2*a*b^2*c*d*cos_integral(((b*x + a)*(b*c/(b*x + a) - a*d/(b*x + a) + d) - 
 b*c + a*d)/b)*sin(-(b*c - a*d)/b) + 2*a^2*b*d^2*cos_integral(((b*x + a)*( 
b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/b)*sin(-(b*c - a*d)/b) - 2 
*(b*x + a)*a*b*(b*c/(b*x + a) - a*d/(b*x + a) + d)*d*cos(-(b*c - a*d)/b)*s 
in_integral(((b*x + a)*(b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/b) 
 + 2*a*b^2*c*d*cos(-(b*c - a*d)/b)*sin_integral(((b*x + a)*(b*c/(b*x + a) 
- a*d/(b*x + a) + d) - b*c + a*d)/b) - 2*a^2*b*d^2*cos(-(b*c - a*d)/b)*sin 
_integral(((b*x + a)*(b*c/(b*x + a) - a*d/(b*x + a) + d) - b*c + a*d)/b...
 
3.1.28.9 Mupad [F(-1)]

Timed out. \[ \int \frac {x^2 \sin (c+d x)}{(a+b x)^2} \, dx=\int \frac {x^2\,\sin \left (c+d\,x\right )}{{\left (a+b\,x\right )}^2} \,d x \]

input
int((x^2*sin(c + d*x))/(a + b*x)^2,x)
 
output
int((x^2*sin(c + d*x))/(a + b*x)^2, x)